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Vlаdislav
@Vlаdislav
July 2022
1
15
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Найдите натуральное число n, для которого выполняется равенство
(c объяснением):
[tex] \frac{4 ^{3}-1 }{4 ^{3}+1 } * \frac{5 ^{3}-1 }{5 ^{3}+1 } *...* \frac{ n^{3}-1 }{n^{3}+1 } = \frac{3906}{4225} [/tex]
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dtnth
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- не подходит (n должно быть натуральным)
ответ: 25
4 votes
Thanks 4
Vlаdislav
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ответ: 25