Вычислить а) [tex]log _{ \frac{1}{ \sqrt{3} } } (9 \sqrt[3]{3} )[/tex] б) [tex]7 ^{log _{7}2 +1} [/tex]. Created by Nightmonster. algebra-ru

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lara164

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Nightmonster спасибо большое

lara164 не за что :)

NNNLLL54

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$log_{\frac{1}{\sqrt3}}(9 \sqrt[3]{3} )= \frac{1}{-\frac{1}{2}} \cdot log_3\, (3^{2+\frac{1}{3}})=-2log_3\, (3^{\frac{7}{3}})=-2\cdot \frac{7}{3}=-\frac{14}{3}\\\\\\7^{log_7\, 2+1}=7^{log_72}\cdot 7^1=2\cdot 7=14\\\\oo$

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