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Dimaj
@Dimaj
July 2022
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Решите пожалуйста уравнение:
[tex] x^{4} [/tex]+121-[tex] 10x^{3} [/tex]-110x-[tex] 2x^{2 } [/tex]=0
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KuOV
Verified answer
Разделим обе части на x²:
x² + 121/x² - 10x - 110/x - 2 = 0
x² + 121/x² - 10(x + 11/x) - 2 = 0
Обозначим x + 11/x = t, тогда t² = (x + 11/x)² = x² + 121/x² + 2·x·11/x
t² = x² + 121/x² + 22, откуда x² + 121/x² = t² - 22
t² - 22 - 10t - 2 = 0
t² - 10t - 24 = 0
t = 12 или t = - 2 по т. Виета
x + 11/x = 12 x + 11/x = - 2
x² - 12x + 11 = 0 x² + 2x + 11 = 0
по т.Виета: D = 4 - 44 < 0
x = 11 нет корней
x = 1
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Answers & Comments
Verified answer
Разделим обе части на x²:x² + 121/x² - 10x - 110/x - 2 = 0
x² + 121/x² - 10(x + 11/x) - 2 = 0
Обозначим x + 11/x = t, тогда t² = (x + 11/x)² = x² + 121/x² + 2·x·11/x
t² = x² + 121/x² + 22, откуда x² + 121/x² = t² - 22
t² - 22 - 10t - 2 = 0
t² - 10t - 24 = 0
t = 12 или t = - 2 по т. Виета
x + 11/x = 12 x + 11/x = - 2
x² - 12x + 11 = 0 x² + 2x + 11 = 0
по т.Виета: D = 4 - 44 < 0
x = 11 нет корней
x = 1