Решите систему неравенств
1)[tex]\left \{ {{x^2-x+6\ \textgreater \ 0} \atop {x^2\leq25 }} \right.[/tex]
2)[tex]\frac{x^2(1-x)}{x^2-6x-9} \leq 0[/tex]
1)[tex]\left \{ {{x^2-x+6\ \textgreater \ 0} \atop {x^2\leq25 }} \right.[/tex]
2)[tex]\frac{x^2(1-x)}{x^2-6x-9} \leq 0[/tex]
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