Упростите выражение: a) [tex]\frac{sin 2a}{2ctga}[/tex] b) [tex]\frac{1-cos 2a}{1+cos 2a}[/tex]. Created by marinakisca0. algebra-ru

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marinakisca0 @marinakisca0

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Упростите выражение:
a) [tex]\frac{sin 2a}{2ctga}[/tex]
b) [tex]\frac{1-cos 2a}{1+cos 2a}[/tex]

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NNNLLL54

Verified answer

$a)\; \; \frac{sin2a}{2\, ctga}=\frac{2\; sina\; cosa}{2\; \frac{cosa}{sina}}=\frac{sin^2a\; cosa}{cosa}=sin^2a\\\\\\b)\; \; \frac{1-cos2a}{1+cos2a}=\frac{2sin^2a}{2cos^2a}=tg^2a$

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