нужно найти производную функции
а)
[tex]3 {x}^{2} - \frac{1}{ {x}^{3} } [/tex]
б)
[tex]( \frac{x}{3} + 7) {}^{6} [/tex]
в)
[tex] \frac{ ln(x) }{1 - x} [/tex]
а)
[tex]3 {x}^{2} - \frac{1}{ {x}^{3} } [/tex]
б)
[tex]( \frac{x}{3} + 7) {}^{6} [/tex]
в)
[tex] \frac{ ln(x) }{1 - x} [/tex]
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Answers & Comments
((x/3+7)^6)'=6*(x/3+7)^5)*
(x/3+7)'=6/3*(x/3+7)^5=
2*(x/3+7)^5
(lnx/(1-x)'=
(1/x*(1-x)+lnx)/(1-x)²