Представьте квадрат двучлена в виде многочлена.
[tex](3 {a}^{2} + 1) {}^{2} \\ (x {}^{2} + y {}^{2} ) {}^{2} [/tex]
[tex](3 {a}^{2} + 1) {}^{2} \\ (x {}^{2} + y {}^{2} ) {}^{2} [/tex]
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Ответ:
(3а^2+1)^2=9а^4+6а^2+1
(х^2+у^2)^2=х^4+2х^2у^2+у^4