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vikayakovleva2
@vikayakovleva2
July 2022
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Помогите пожалуйста
а)log 1/2 (x-2)[tex] \geq [/tex]1
б)3^x-2>9
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Answers & Comments
zarembo73
A) log_1/2(x-2)≥1;
log_1/2(x-2)≥log_1/2(1/2);
Так как 1/2<1, то:
x-2≤1/2;
x≤1/2+2;
x≤2,5.
ОДЗ:
x-2>0;
x>2.
Общее решение: x∈(2;2,5].
Ответ: (2;2,5].
б)
Ответ: (4;+∞).
1 votes
Thanks 1
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Answers & Comments
log_1/2(x-2)≥log_1/2(1/2);
Так как 1/2<1, то:
x-2≤1/2;
x≤1/2+2;
x≤2,5.
ОДЗ:
x-2>0;
x>2.
Общее решение: x∈(2;2,5].
Ответ: (2;2,5].
б)
Ответ: (4;+∞).