[tex] (\frac{2}{3})^2^x* (\frac{9}{16})^2^x= \frac{3}{8} [/tex]. Created by GuvirMaxim. algebra-ru

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[tex] (\frac{2}{3})^2^x* (\frac{9}{16})^2^x= \frac{3}{8} [/tex]

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$( \frac{2}{3} )^{2x}*( \frac{9}{16} )^{2x}= \frac{3}{8} \\ \\ ( \frac{2}{3} *\frac{9}{16} )^{2x}= \frac{3}{8} \\ \\ ( \frac{3}{8} )^{2x}= (\frac{3}{8})^1 \\ \\ 2x=1 \\ x=0.5$

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