решите неравенство, срочно
[tex] \sin( \frac{x}{4} + \frac{\pi}{6} ) > \frac{ \sqrt{2} }{2} [/tex]
[tex] \sin( \frac{x}{4} + \frac{\pi}{6} ) > \frac{ \sqrt{2} }{2} [/tex]
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Answers & Comments
pi/4-pi/6<x/4<3pi/4-pi/6
4(pi/4-pi/6)<x<4(3pi/4-pi/6)
pi/3<x<7pi/3