Решите неравенство:
[tex] log_{15}(x^2-6x+8)\geq log_{x-1}(x^2-6x+8) [/tex]
[tex] log_{15}(x^2-6x+8)\geq log_{x-1}(x^2-6x+8) [/tex]
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_________________________Решено при помощи метода рационализации с учётом О.Д.З.
ОТВЕТ: ( 1 ; 3 - √2 ] U ( 4 ; 3 + √2 ] U [ 16 ; + ∞ )