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azaqr @azaqr

July 2022 2 8 Report

Решить систему уравнений:

[tex]\left \{ {x+4y+2\sqrt{xy}=12 } \atop {x+4y-2\sqrt{xy} =4}} \right.[/tex]

m11m

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Ответ:

Объяснение:

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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NNNLLL54

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$\left\{\begin{array}{ccc}x+4y+2\sqrt{xy}=12\\x+4y-2\sqrt{xy}=4\end{array}\right\; \oplus \ominus \; \left\{\begin{array}{ccc}2x+8y=16\\4\sqrt{xy}=8\end{array}\right\; \; \left\{\begin{array}{ccc}x=8-4y\\xy=4\end{array}\right\\\\(8-4y)\cdot y=4\\\\4y^2-8y+4=0\; |:4\\\\y^2-2y+1=0\\\\(y-1)^2=0\; \; \to \; \; y-1=0\\\\y=1\; \\\\x=8-4\cdot 1=4\\\\Otvet:\; \; (4,1)\; .$

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Answers & Comments

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