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@Алинкус
March 2022
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Пожалуйста помогите 35 баллов
Найдите значение суммы:
[tex] ctg60+ctg^{2} 60+ ctg^{3}60+...+ ctg^{n} 60[/tex]
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Verified answer
Ctg60°=1/√3,
ctg60°,ctg²60°,ctg³60°,..., ctgⁿ60° - n членов геометрической прогрессии,
Sn=b₁(1-qⁿ)/(1-q) , b₁=ctg60°=1/√3, q=ctg60°=1/√3,
Sn=(1/√3)(1-(1/√3)ⁿ)/(1-(1/√3)) или
Sn=[(√3ⁿ)-1](√3+1)/[2(√3
ⁿ)]
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Answers & Comments
Verified answer
Ctg60°=1/√3,ctg60°,ctg²60°,ctg³60°,..., ctgⁿ60° - n членов геометрической прогрессии,
Sn=b₁(1-qⁿ)/(1-q) , b₁=ctg60°=1/√3, q=ctg60°=1/√3,
Sn=(1/√3)(1-(1/√3)ⁿ)/(1-(1/√3)) или
Sn=[(√3ⁿ)-1](√3+1)/[2(√3ⁿ)]