Помогите решить пример)
[tex] \frac{ x^{2} -5x-6}{ x^{2} -4x-5} = 0[/tex]
[tex] \frac{ x^{2} -5x-6}{ x^{2} -4x-5} = 0[/tex]
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x² -5x-6=0
D=25+24=49
x₁= 5-7 = -1
2
x₂ = 5+7 =6
2
x²-5x-6=(x+1)(x-6)
x²-4x-5=0
D=16+20=36
x₁= 4-6 = -1
2
x₂ = 4+6 =5
2
x² -4x-5 = (x+1)(x-5)
(x+1)(x-6) =0
(x+1)(x-5)
ОДЗ: х≠ -1
х=5
x-6 =0
x+5
x-6=0
x=6
Ответ: 6.