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(Подробно)[tex] \frac{(x-2)^2}{log(2x, (2x-x^2))} [/tex]
(Подробно)[tex] \frac{(x-2)^2}{log(2x, (2x-x^2))} [/tex]
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Answers & Comments
2x-x²>0
x(2-x)> 2-x>0 ⇒x<2
2x-x²≠1 т.к ㏒₂ₓ(1)=0, а на 0 делить нельзя
х²-2х+1=0
D=4-4=0
x≠1
x∈(0;1/2)∪(1/2;1)∪(1;2)