Найдите значения выражений[tex]81 ^{log _{9}2-0.25log _{3}2 } [/tex]. Created by umbrella2281. algebra-ru

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umbrella2281 @umbrella2281

August 2021 1 18 Report

Найдите значения выражений
[tex]81 ^{log _{9}2-0.25log _{3}2 } [/tex]

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NNNLLL54

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$81^{log_92-0,25log_32}=(3^4)^{log_{3^2}2-\frac{1}{4}log_32}=3^{4\cdot \frac{1}{2}log_32}\cdot 3^{-4\cdot \frac{1}{4}log_32}=\\\\=3^{2log_32}\cdot 3^{-log_32}=3^{log_34}\cdot 3^{log_3\frac{1}{2}}=4\cdot \frac{1}{2}=2$

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