Упростите:
[tex] \frac{ \sin {}^{2} (90 - a) }{1 - \cos {}^{2} (90 - a) } [/tex]
[tex] \frac{ \sin {}^{2} (90 - a) }{1 - \cos {}^{2} (90 - a) } [/tex]
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Відповідь:1
Пояснення:
Sin^2(90-x)/1-cos^2(90-x) =sin^2(90-x)/sin^2(90-x)=1