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FDdragon
@FDdragon
July 2022
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Помогите решить
[tex]log^2_3x+2\ \textgreater \ 3log_3x[/tex]
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MizoriesKun
㏒₃²x+2>3㏒₃x ОДЗ х>0
㏒₃²x-3㏒₃x +2> 0 замена ㏒₃x =а
а²-3а+2=0
D=9-8=1
a₁=(3+1)/2=2 ㏒₃x =2 x=9
a₂=(3-1)/2=1 ㏒₃x =1 x=3
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Answers & Comments
㏒₃²x-3㏒₃x +2> 0 замена ㏒₃x =а
а²-3а+2=0
D=9-8=1
a₁=(3+1)/2=2 ㏒₃x =2 x=9
a₂=(3-1)/2=1 ㏒₃x =1 x=3