[tex]\frac{10}{cos^{2}92+1+cos^{2}182}[/tex]
cos92=cos(90+2)=-sin2
cos182=cos(180+2)=-cos2
cos^2(2)+sin^2(2)=1
10/2=5
10/(cos^2 92 + 1 + cos^2 182) =
10/(-sin^2 2 + 1 - cos^2 2) = 10/(1-1)=10/0
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Answers & Comments
cos92=cos(90+2)=-sin2
cos182=cos(180+2)=-cos2
cos^2(2)+sin^2(2)=1
10/2=5
10/(cos^2 92 + 1 + cos^2 182) =
10/(-sin^2 2 + 1 - cos^2 2) = 10/(1-1)=10/0