[tex] \frac{2sin2a + cos( \frac{3pi}{2} - a ) - sin (pi + a) }{1 + sin ( \frac{3pi}{2} - a)} [/tex]. Created by 122142124. algebra-ru

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[tex] \frac{2sin2a + cos( \frac{3pi}{2} - a ) - sin (pi + a) }{1 + sin ( \frac{3pi}{2} - a)} [/tex]

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Sophie155 $\frac{2sin2 \alpha + cos( \frac{3 \pi }{2} - \alpha ) - sin ( \pi + \alpha ) }{1 + sin ( \frac{3 \pi }{2} - \alpha )} = \frac{2sin2 \alpha -sin \alpha + sin \alpha }{1 - cos \alpha} = \frac{2sin2 \alpha }{1 - cos \alpha} =$ $= \frac{2sin2 \alpha }{2sin^2 \frac{ \alpha }{2} } =\frac{sin2 \alpha }{sin^2 \frac{ \alpha }{2} } =\frac{2sin \alpha cos \alpha }{sin^2 \frac{ \alpha }{2} } =\frac{2*2sin \frac{ \alpha }{2} cos \frac{ \alpha }{2} cos \alpha }{sin^2 \frac{ \alpha }{2} } = \frac{4cos \frac{ \alpha }{2}cos \alpha }{sin \frac{ \alpha }{2} } =$ $=4ctg \frac{ \alpha }{2}cos \alpha$

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2 vyberite iz predlozhennyh utverzhdenij pravilnye vypishite ih nomera 1 dvoev

skolko budet x 23

zabyl kak najti x pomogite x2

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