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кот02
@кот02
August 2022
1
9
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Найдите значение выражения
48*sin
[tex] 75^{0
} [/tex]
cos
[tex]75^{0} [/tex]
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Answers & Comments
yellok
48*sin75cos75=48/2*(sin(75+75)+sin(75-75))=24*(sin150+sin0)=
=24*(sin(90+60)+0)=24*cos60=24*1/2=12
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Answers & Comments
=24*(sin(90+60)+0)=24*cos60=24*1/2=12