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KarinaO
@KarinaO
July 2022
1
5
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[tex]tg \frac{20 \pi }{3} =[/tex]
[tex]tg \frac{28 \pi }{3} =[/tex]
[tex]tg(- \frac{31 \pi }{6} )=
[/tex]
[tex]ctg \frac{16 \pi }{3}
[/tex]
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kostet1998
Tg
=tg(7π-
) =-tg
=-√3
tg
=tg(9π+
) =tg
=√3
tg(-
)=-tg
=-tg(5π+
)=-tg
=-
ctg
=ctg(5π+
)=ctg
=
4 votes
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Answers & Comments
tg=tg(9π+) =tg=√3
tg(-)=-tg=-tg(5π+)=-tg=-
ctg=ctg(5π+)=ctg=