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sashakim17
@sashakim17
August 2022
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Решите уравнения:
[tex] \frac{2x-3}{4} -3x= \frac{x+1}{2} [/tex]
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Lesben
2х-3 / 4 - 3х = х+1 / 2 I*4
2х-3-3х*4 = 2(х+1)
2х-3-12х = 2х+2
-12х = 2+3
-12х = 5
х = 5: (-12)
х = -5/12
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ВикаВикторовна
Verified answer
(2x-3)/4 - 3x = (x+1)/2 /.4
(2x-3) -12x = 2(x+1)
2x-3-12x=2x+2
-10x-3=2x+2
-10x-2x=2+3
-12x=5
x=-5/12
0 votes
Thanks 0
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Answers & Comments
2х-3-3х*4 = 2(х+1)
2х-3-12х = 2х+2
-12х = 2+3
-12х = 5
х = 5: (-12)
х = -5/12
Verified answer
(2x-3)/4 - 3x = (x+1)/2 /.4(2x-3) -12x = 2(x+1)
2x-3-12x=2x+2
-10x-3=2x+2
-10x-2x=2+3
-12x=5
x=-5/12