Помогите решить [tex]( \frac{x+5y}{x^2-5xy}- \frac{x-5y}{x^2+5xy} )* \frac{x^2-25y^2 }{5y^2} [/tex]. Created by Qewrei. algebra-ru

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Qewrei @Qewrei

July 2022 1 0 Report

Помогите решить
[tex]( \frac{x+5y}{x^2-5xy}- \frac{x-5y}{x^2+5xy} )* \frac{x^2-25y^2 }{5y^2} [/tex]

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oganesbagoyan

Verified answer

----------------
( (x+5y)/x(x-5y) - (x-5y)/x(x+5y)) *(x² -25y²)/5y² =
( (x+5y)² - (x-5y)²) ) / x(x²-25y²) *(x -5y)(x+5y)/5y² =
( (x+5y - x+5y)(x+5y + x-5y) ) * (1/ x(x²-25y²) ) * (x² -25y²)/5y² =
20xy/5xy² =4/y.

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