Упростите выражение: [tex]2cos(\pi-\alpha)+(\frac{sin\alpha+tg}{tg\alpha})^{2}-cos^{2}\alpha[/tex]. Created by MonsterLev. algebra-ru

tex]...

March 2022 2 10 Report

Упростите выражение:

[tex]2cos(\pi-\alpha)+(\frac{sin\alpha+tg}{tg\alpha})^{2}-cos^{2}\alpha[/tex]

Quintessence

$2cos(\pi-\alpha)+(\frac{sin\alpha+tg\alpha}{tg\alpha})^2-cos^2\alpha=-2cos\alpha+(\frac{sin\alpha}{tg\alpha}+\frac{tg\alpha}{tg\alpha})^2-cos^2\alpha=-2cos\alpha+(cos\alpha+1)^2-cos^2\alpha=-2cos\alpha+cos^2\alpha+2cos\alpha+1-cos^2\alpha=1$

1 votes Thanks 0

Artem112

Verified answer

2cos(π-α)+(sinα+tgα/tgα)²-cos²α;

Пошагово:

1) 2cos(π-α)=-2cosα;

2) sinα+tgα/tgα=(sinα*cosα+sinα)/cosα/tgα=cosα+1;

-2cosα+(cosα+1)²-cos²α=-2cosα+cos²α+2cosα+1-cos²α=1.

Ответ: 1.

1 votes Thanks 0

Answers & Comments

Verified answer

najdite znachenie vyrvzheniya s obyasneniyami

рекомендуемые вопросы

Helpful Links

Helpful Social