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mariomshina
@mariomshina
July 2022
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Вычислите : [tex] 8^{log _{2} 5-log _{27} 3[/tex]
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iqLL
Log27 3 =1/3
8^log2 5 *8^-1/3
2^3log2 5 /2=125/2
1 votes
Thanks 1
mariomshina
не совсем понятна вторая строчка,почему там так
iqLL
Это свойство степени
iqLL
а^(b-c)=a^b*a^c
iqLL
a^-c
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Answers & Comments
8^log2 5 *8^-1/3
2^3log2 5 /2=125/2