Вычислить значение из каждой тригонометрической функций,если : cos a= 0.6 и
0 < a < [tex] \frac{p}{2} [/tex]
0 < a < [tex] \frac{p}{2} [/tex]
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tg a = sin a/cos a = 0,8/0,6 = 4/3
ctg a = 1/tg a = 1 * 3/4 = 3/4 = 0,75
Ответ: 0,8; 4/3; 0,75
sin^a=1-cos^2a=1-0.36=0.64 0<cosa<1
sina=√0.64=0.8 0<sina<1
tga=sina/cosa=0.8/0.6=1.33
ctga=cosa/sina=0.6/0.8=0.75