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pokipoki
@pokipoki
July 2022
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Помогите решить,пожалуйста :)
[tex] 7^{x+3} - 9^{0.5x+1.5}\ \textless \ 6* 7^{x+2} - 2* 3^{x+2} [/tex]
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kirichekov
Verified answer
7^(x+3)-9^(0,5x+1,5)<6*7^(x+2)-2*3^(x+2)
(7^x)*7³-6*(7^x)*7²<(3²)^(0,5x+1,5)-2*(3^x)*3²
49*7^x<(3^x)*3³-(3^x)*18
49*7^x<9*(3^x)
7(x+2)<3^(x+2) |:3^(x+2)
(7/3)^(x+2)<1
(7/3)^(x+2)<(7/3)⁰. a=7/3, 7/3>1 знак неравенства не меняем
x+2<0
x<-2
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Answers & Comments
Verified answer
7^(x+3)-9^(0,5x+1,5)<6*7^(x+2)-2*3^(x+2)(7^x)*7³-6*(7^x)*7²<(3²)^(0,5x+1,5)-2*(3^x)*3²
49*7^x<(3^x)*3³-(3^x)*18
49*7^x<9*(3^x)
7(x+2)<3^(x+2) |:3^(x+2)
(7/3)^(x+2)<1
(7/3)^(x+2)<(7/3)⁰. a=7/3, 7/3>1 знак неравенства не меняем
x+2<0
x<-2