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rakhmankadirov1
@rakhmankadirov1
July 2022
1
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Найти область определения с функции:[tex]1)y= \frac{7cos3x}{3x-18}\\ 2)y= \sqrt[6]{ \frac{2x-5}{6-3x}}[/tex]
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sedinalana
Verified answer
1
3x-18≠0
3x≠18
x≠6
x∈(-∞;6) U (6;∞)
2
(2x-5)/(6-3x)≥0
x=2,5 x=2
_ + _
----------------(2)-----------------[2,5]----------------
x∈)2;2,5]
1 votes
Thanks 0
rakhmankadirov1
это правильно
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Answers & Comments
Verified answer
13x-18≠0
3x≠18
x≠6
x∈(-∞;6) U (6;∞)
2
(2x-5)/(6-3x)≥0
x=2,5 x=2
_ + _
----------------(2)-----------------[2,5]----------------
x∈)2;2,5]