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vlad37694
@vlad37694
July 2022
1
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Решите Систему Неравенств Распишите Подробно Пожайлуста Девушке:)) [tex] \left \{ {{2x+3 \leq 4*(x-1)+13} \atop {x-1\ \textless \ 2*(3x-16)}} \right. [/tex]
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belozerova1955
2х+3≤4·(х-1)+13
х-1<2·(3x-16)
2x+3≤4x-4+13
x-1<6x-32
2x-4x≤-4+13-3
x-6x<-32+1
-2x≤6
-5x<-31
x≥-3
x>6,2
Ответ: х>6,2
или х∈(6,2; +∞)
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Answers & Comments
х-1<2·(3x-16)
2x+3≤4x-4+13
x-1<6x-32
2x-4x≤-4+13-3
x-6x<-32+1
-2x≤6
-5x<-31
x≥-3
x>6,2
Ответ: х>6,2
или х∈(6,2; +∞)