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love04arianna
@love04arianna
August 2022
1
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Избавьтесь от иррациональности в знаменателе дроби:
1/[tex] \sqrt{13} [/tex]-3-[tex] \sqrt{21-12 \sqrt{3} } [/tex]
Приведите дробь к виду [tex] \sqrt{a} [/tex]+[tex] \sqrt{b} [/tex].
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sedinalana
21-12√3=(2√3-3)²
√(2√3-3)²=|2√3-3|=2√3-3
1/(√13 -3 -√(21-12√3)=1/(√13 -3-2√3+3)=1/(√13-2√3)=
=(√13+2√3)/(√13-2√3)(√13+2√3)=(√13+2√3)/(13-12)=√13+2√3
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Answers & Comments
√(2√3-3)²=|2√3-3|=2√3-3
1/(√13 -3 -√(21-12√3)=1/(√13 -3-2√3+3)=1/(√13-2√3)=
=(√13+2√3)/(√13-2√3)(√13+2√3)=(√13+2√3)/(13-12)=√13+2√3