[tex] \frac{ b^{2} }{36 a^{2}- b^{2} } : \frac{b}{6a-b} [/tex] при a = [tex] \frac{1}{6} [/tex], b = [tex] \frac{1}{9} [/tex]. Created by Simon026. algebra-ru

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June 2022 1 10 Report

[tex] \frac{ b^{2} }{36 a^{2}- b^{2} } : \frac{b}{6a-b} [/tex] при a = [tex] \frac{1}{6} [/tex], b = [tex] \frac{1}{9} [/tex]

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tamarabernukho

Verified answer

$\frac{ b^{2} }{(6a-b)(6a+b) } * \frac{6a-b}{b} = \frac{b}{6a+b} = \frac{ \frac{1}{9} }{6* \frac{1}{6} + \frac{1}{9} } = \frac{1}{9} * \frac{9}{10} =0.1$

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Answers & Comments

Verified answer

mozhno li nablyudat solnechnoe zatmenie nahodyas na drugih planetah solnechnoj sis

my nashli bolshoj muravejnik pod elyuno ni odnogo ryzhego muravya my ne uvideli

v hodu borby s aziatskimi kochevnikami zavoevatelyami v egipte byla sozdana novaya

2600 g do n e 1490 1436 gg do n e 1300 g do ne skolko vekov nazad

posle rasprostraneniya sredi evreev zheleznyh orudij vse bolshe stalo poyavlyatsya b

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