1-2[tex] log_{15} [/tex]3=[tex]log_{15} [/tex]5 - [tex]log_{15} [/tex](2x+1)Легкое.. но все же... Created by AlyonaF. algebra-ru

tex](2x+1)Легкое.. но все же...

July 2022 1 10 Report

1-2[tex] log_{15} [/tex]3=[tex]log_{15} [/tex]5 - [tex]log_{15} [/tex](2x+1)
Легкое.. но все же..

Answers & Comments

mailforazi $log_{15}15-log_{15}3^2=log_{15}5-log_{15}(2x+1) \\ \\ log_{15} \frac{15}{9} =log_{15} \frac{5}{2x+1} \\ \\ \frac{5}{3} = \frac{5}{2x+1} \\ \\ 3=2x+1 \\ \\ x=1$

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