Разложите на множители выражение:
1)6ab-3ac+[tex] 2b^{2} [/tex]-bc
2)[tex] x^{k+1} + 2x^{k} -x-2 [/tex]
1)6ab-3ac+[tex] 2b^{2} [/tex]-bc
2)[tex] x^{k+1} + 2x^{k} -x-2 [/tex]
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2) x^k*x+2x^k-x-2=x^k(x+2)-(x+2)=
=(x+2)(x^k-1)