Решите квадратное уравнение, разлагая его левую часть на множители: [tex] 4x^{2} -\frac{1}{144} =0 [/tex]. Created by Aleksa0Jane0Malfoy. algebra-ru

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4х² - 1\144=0

(2х - 1\12) (2х + 1\12) = 0

2х - 1\12 = 0; 2х = 1\12; х = 1\24

2х + 1\12 = 0; 2х = -1\12; х=-1\24.

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$4x^{2} -\frac{1}{144} =0\\ \\ (2x-\frac{1}{12})( 2x+\frac{1}{12})=0\\ \\ 2x-\frac{1}{12}=0\ or \ 2x+\frac{1}{12}=0\\ \\ 2x=\frac{1}{12} \ or \ 2x=-\frac{1}{12} \\ \\ x=\frac{1}{24} \ or \ x=-\frac{1}{24}$

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