tex])...

July 2022 2 7 Report

ДАЮ 100 БАЛЛОВ за тригометрию

найдите 14cosA если sinA = [tex]\frac{4\sqrt[]{3} }{7}[/tex]

A ⊂(0;[tex]\frac{\pi }{2}[/tex])

table123

Ответ:

$\displaystyle sinA=\frac{4\sqrt3}{7}\\\\cos^2A=1-sin^2A=1-\dfrac{48}{49}=\frac{1}{49}\ \ ,\ \ \ cosA=\pm \frac{1}{7}\\\\\angle {A}\in \Big(0;\frac{\pi }{2}\Big)\ \ \ \Rightarrow\ \ \ cosA>0\ \ ,\ \ \ cosA=\frac{1}{7}\\\\14\, cosA=\frac{14}{7}=2$

0 votes Thanks 1

NNNLLL54

Verified answer

Ответ: 2

Объяснение: ( ^ - знак степени)

cos^2 A =1-sin^2 A =1- 48/49=1/49, cosA =1/ 7

14cosA=14*1/7 =2

1 votes Thanks 0

Answers & Comments

Verified answer

pomogite s istoriej pzh87373bca4c100a78bea0c3defb077241 25389

pomogite s anglijskim pzha669c9cb18419ef3637e896e0be84618 85706

algebra 8 klasspomogite reshit tolko 2 7 9tolko 2 7 9ochen srochno tema nerav

mozhno pozhalujsta libo reshenie libo prosto podrobnoe obyasnenenie kak chto delat

pomogite postroit sechenie pozhalujstanado tolko pod bukvoj aesli ne slozhno ras

рекомендуемые вопросы

Helpful Links

Helpful Social