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dimadimka000
@dimadimka000
August 2022
2
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[tex] 1) \frac{4}{x-1}- \frac{8}{x^2+x+1}= \frac{11}{x^3-1}
[/tex]
[tex] 2) \frac{2+x}{9x^2-4}- \frac{2-x}{9x^2+12x+4}= \frac{2}{3x-2}
[/tex]
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pomoshnik09
1) 4*(x²+x+1)-8(x-1)-11=0 . x³-1≠0
4x²+4x+4-8x+8-11=0
4x²-4x+1=0
(2x-1)²=0 2x-1=0 2x=1 x=0.5 ответ0,5
2) (2+х)(3х+2)-(2-х)(3х-2)-2(9х²+12х+4)=0
3х²+8х+4-(6х-4-3х²+2х)-18х²-24х-8=0
3х²+8х+4-6х+4+3х²-2х-18х²-24х-8=0
-12х²-24х=0
-12х(х+2)=0 х=0 х=-2
ответ0,,-2
2 votes
Thanks 1
Dashulya31
1)4(x²+x+1)-8(x-1)=11
4x²+4x+4-8x+8-11=0
4x²-4x+1=0
D=16-4*4*1=0, D=0
x₁=4/8=1/2
ОДЗ: x³-1≠0
(x-1)≠0 или (x²+x+1)≠0
x≠1 или нет корней.
x²+x+1=0
D=1-4*1*1=-3, D<0
нет корней
ответ: х=1/2
2 votes
Thanks 1
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Answers & Comments
4x²+4x+4-8x+8-11=0
4x²-4x+1=0
(2x-1)²=0 2x-1=0 2x=1 x=0.5 ответ0,5
2) (2+х)(3х+2)-(2-х)(3х-2)-2(9х²+12х+4)=0
3х²+8х+4-(6х-4-3х²+2х)-18х²-24х-8=0
3х²+8х+4-6х+4+3х²-2х-18х²-24х-8=0
-12х²-24х=0
-12х(х+2)=0 х=0 х=-2
ответ0,,-2
4x²+4x+4-8x+8-11=0
4x²-4x+1=0
D=16-4*4*1=0, D=0
x₁=4/8=1/2
ОДЗ: x³-1≠0
(x-1)≠0 или (x²+x+1)≠0
x≠1 или нет корней.
x²+x+1=0
D=1-4*1*1=-3, D<0
нет корней
ответ: х=1/2