упростите выражение и найдите его значение при y=3
[tex]\frac{y-2}{y^{2}-1} -\frac{y-1}{y^{2}+y} =[/tex]
[tex]\frac{y+1}{y^{2}-4}-\frac{y-4}{y^{2}-2y=[/tex]
(y-2)/(y^2-1) - (y-1)/(y^2+y)= (y-2)/(y-1)(y+1) - (y-1)/y(y+1)=
[(y(y+1)(y-2)-(y-1)(y-1)(y+1)]/y(y-1)(y+1)=(y+1)(y(y+1)-(y-1)^2)/(y(y+1)(y-1)=
= (y+1)(y^2-2y-y^2+2y-1)/y(y-1)(y+1)= (y+1)/y(y+1)(y-1)=1/y(y-1)
при у=3 получим 1/6
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Answers & Comments
(y-2)/(y^2-1) - (y-1)/(y^2+y)= (y-2)/(y-1)(y+1) - (y-1)/y(y+1)=
[(y(y+1)(y-2)-(y-1)(y-1)(y+1)]/y(y-1)(y+1)=(y+1)(y(y+1)-(y-1)^2)/(y(y+1)(y-1)=
= (y+1)(y^2-2y-y^2+2y-1)/y(y-1)(y+1)= (y+1)/y(y+1)(y-1)=1/y(y-1)
при у=3 получим 1/6