найти производную g(x) x^3 +2x x0= 2
g(x)=[tex]g(x)= x^{3} +2x
g(x)= (\sqrt{x} +1) \sqrt{x} [/tex]
g(x)=[tex]g(x)= x^{3} +2x
g(x)= (\sqrt{x} +1) \sqrt{x} [/tex]
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Answers & Comments
3x²+2=0
3x²=-2
x²=-2/3-не имеет смысла
g¹(x)=1/(2*√x) *√x+1/(2*√x) *√x+1/(2*√x) =1/2+1/2+1/(2*√x) =1/4+1/(2*√x)