[tex] \frac{sin20 ^{0} + cos290 ^{0} }{2sin10^{0} * cos10 ^{0}} \\ [/tex]. Created by MonteTrix. algebra-ru

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[tex] \frac{sin20 ^{0} + cos290 ^{0} }{2sin10^{0} * cos10 ^{0}} \\ [/tex]

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$\frac{sin 20к+cos290к}{2sin10кcos10к} = \frac{sin 20к+cos(270к+20к)}{2sin10кcos10к} =\frac{sin 20к+sin20к}{sin 20к} = \frac{2sin 20к}{sin20к}=2$

$sin2 \alpha =2sin \alpha cos \alpha$
$cos(270к+ \alpha)=sin \alpha$

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