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LizaForever14
@LizaForever14
July 2022
1
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Помогите пожалуйста! Очень прошу! Решите!
[tex] \frac{3x-1}{10} - \frac{4y+1}{5} = -3
^\frac{2x+1}{3} - \frac{3y-2}{8} = 3
[/tex]
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Verified answer
Умножаем обе части уравнения
(3x - 1) / 10 - (4y + 1)/5 = -3 | * 10
(2x + 1)/3 - (3y - 2)/8 = 3 | * 24
3x - 1 -2*(4y + 1) = -30
8*(2x + 1) - 3*(3y - 2) = 72
Приводим подобные слагаемые
3x - 1 - 8y - 2 = -30
16x + 8 - 9y + 6 = 72
3x - 8y = -27
16x - 9y = 58
Выражаем х через у
x = (-27 + 8y)/3
16*(-27 + 8y)/3 - 9y = 58
Решаем второе уравнение
16*(-27 + 8y)/3 - 9y = 58 | *3
16*(-27+8y) - 27y = 174
-432 + 128y - 27y = 174
101y = 174 + 432
y = 6
Находим х
x = (-27 + 8*6)/3 = (-27 + 48) / 3 = 21/3 = 7
Ответ: (7 ;6)
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Answers & Comments
Verified answer
Умножаем обе части уравнения(3x - 1) / 10 - (4y + 1)/5 = -3 | * 10
(2x + 1)/3 - (3y - 2)/8 = 3 | * 24
3x - 1 -2*(4y + 1) = -30
8*(2x + 1) - 3*(3y - 2) = 72
Приводим подобные слагаемые
3x - 1 - 8y - 2 = -30
16x + 8 - 9y + 6 = 72
3x - 8y = -27
16x - 9y = 58
Выражаем х через у
x = (-27 + 8y)/3
16*(-27 + 8y)/3 - 9y = 58
Решаем второе уравнение
16*(-27 + 8y)/3 - 9y = 58 | *3
16*(-27+8y) - 27y = 174
-432 + 128y - 27y = 174
101y = 174 + 432
y = 6
Находим х
x = (-27 + 8*6)/3 = (-27 + 48) / 3 = 21/3 = 7
Ответ: (7 ;6)