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Horan69
@Horan69
August 2022
1
8
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сколько молекул в 44,8 л метана [tex]CH ^{4} [/tex] ?
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udodovi
n=V/Vm=44.8л/22.4л/моль=моль
N=n*NA=2моль*6.02*10²³=12.02*10²³молекул
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n=V/Vm=44.8л/22.4л/моль=моль
N=n*NA=2моль*6.02*10²³=12.02*10²³молекул