Решите на множестве R неравенство [tex]\frac{log_{\frac{1}{2}}x^{2}+4}{\sqrt{3x+1}}\geq0[/tex]
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Решите на множестве R неравенство [tex]\frac{log_{\frac{1}{2}}x^{2}+4}{\sqrt{3x+1}}\geq0[/tex]
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Одз: х>=-1/3
log1/2(x^2)>=-4
log1/2(x^2)>=log1/2(16)
x^2<=16
-4<=х<=4
с учетом одз
-1/3<=x<=4