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80LK
@80LK
July 2022
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Решите уравнение[tex] x^{2} = (2x-8)^{2}[/tex]
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X^2=(2x-8)^2
x=2x-8
x=8-2x
x-2x=-8
x+2x=8
-x=-8
3x=8
x=8
x=8/3
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80LK
Извените первый x в 4, а не 2
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Answers & Comments
x=2x-8
x=8-2x
x-2x=-8
x+2x=8
-x=-8
3x=8
x=8
x=8/3