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golubovamasha2
@golubovamasha2
August 2022
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помогите пожалуйста
[tex] 2^{log^2 2x} + 2^{log^2 2x} \leq 2^8[/tex]
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sedinalana
Verified answer
2*2^log²(2)x ≤2^8
2^log²(2)x ≤2^7
log²(2)x≤7
(log(2)x-√7)(log(2)x+√7)≤0
-√7≤log(2)x≤√7
x∈
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golubovamasha2
как вы получили первую строчку???????
golubovamasha2
почему 2*2 в степени логарифм..?
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Answers & Comments
Verified answer
2*2^log²(2)x ≤2^82^log²(2)x ≤2^7
log²(2)x≤7
(log(2)x-√7)(log(2)x+√7)≤0
-√7≤log(2)x≤√7
x∈