- x³ + 3x - 2 = 0
x³ - 3x + 2 = 0
(x³ - 1) - (3x - 3) = 0
(x - 1)(x² + x + 1) - 3(x - 1) = 0
(x - 1)(x² + x + 1 - 3) = 0
(x - 1)(x² + x - 2) = 0
(x - 1)(x + 2)(x - 1) = 0
или x - 1 = 0 и тогда x = 1
или x + 2 = 0 и тогда x = - 2
Ответ : - 2 ; 1
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Verified answer
- x³ + 3x - 2 = 0
x³ - 3x + 2 = 0
(x³ - 1) - (3x - 3) = 0
(x - 1)(x² + x + 1) - 3(x - 1) = 0
(x - 1)(x² + x + 1 - 3) = 0
(x - 1)(x² + x - 2) = 0
(x - 1)(x + 2)(x - 1) = 0
или x - 1 = 0 и тогда x = 1
или x + 2 = 0 и тогда x = - 2
Ответ : - 2 ; 1