помогите вычислить множитель
[tex]\sqrt{12}[/tex]
[tex]\sqrt{44}[/tex]
[tex]\sqrt{63}[/tex]
[tex]\sqrt{125}[/tex]
[tex]\sqrt{343}[/tex]
[tex]\sqrt{882}[/tex]
[tex]\sqrt{12}[/tex]
[tex]\sqrt{44}[/tex]
[tex]\sqrt{63}[/tex]
[tex]\sqrt{125}[/tex]
[tex]\sqrt{343}[/tex]
[tex]\sqrt{882}[/tex]
Answers & Comments
Ответ:
Verified answer
Так или по другому. Я нописала так
\begin{gathered}\displaystyle \sqrt{12} = \sqrt{4*3} =2\sqrt{3} \\\\\sqrt{44} =\sqrt{4*11} =2\sqrt{11} \\\\\sqrt{63} =\sqrt{9*7} =3\sqrt{7} \\\\\sqrt{125} =\sqrt{25*5} =5\sqrt{5} \\\\\sqrt{343} =\sqrt{49*7} =7\sqrt{7} \\\\\sqrt{882} = \sqrt{9*49*2} =3*7\sqrt{2} =21\sqrt{2}\end{gathered}
12
=
4∗3
=2
3
44
=
4∗11
=2
11
63
=
9∗7
=3
7
125
=
25∗5
=5
5
343
=
49∗7
=7
7
882
=
9∗49∗2
=3∗7
2
=21
2