Обчисліть [tex]256^{0,75}*((-1/5)^{-2}-49^{0})[/tex]. Created by dimaonopko2020. algebra-ru

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dimaonopko2020 @dimaonopko2020

July 2022 2 12 Report

Обчисліть [tex]256^{0,75}*((-1/5)^{-2}-49^{0})[/tex]

Ответ:

$256^{0,75}\cdot *\Big(\Big(-\dfrac{1}{5}\Big)^{-2}-49^0\Big)=(2^8)^{\frac{3}{4}}\cdot \Big((-5)^2-1\Big)=2^6\cdot (25-1)=\\\\\\=64\cdot 24=1536$

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Ответ:

1536

Объяснение:

${256}^{0.75} \times( ( - \frac{ 1}{5}) ^{ - 2} - {49}^{0} ) = ( {2}^{8} )^{ \frac{3}{4} } \times (( - \frac{5}{1} )^{2} - 1 ) = {2}^{8 \times \frac{3}{4} } \times (( { - 5})^{2} - 1 )= {2}^{6} \times ({5}^{2} - 1) = 64* (25-1) = 64*24 = 1536$

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