Помогите пожалуйста!! сократите дробь: 1)[tex] \frac{(n+1)!}{n!} [/tex] 2)[tex] \frac{(n+1)!(n+3)}{(n+4)!} [/tex]. Created by NastasiaRediska. algebra-ru

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$\frac{(n+1)!}{n!} = \frac{(n+1)*n!}{n!} =n+1






$

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$\frac{(n+1)!(n+3)}{(n+4)!}=\frac{1}{(n+2)(n+4)}$

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NNNLLL54 Неверно

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$1)\quad \frac{(n+1)!}{n!}=\frac{n!\; (n+1)}{n!}=n+1\\\\2)\quad \frac{(n+1)!\; (n+3)}{(n+4)!}=\frac{(n+1)!\; (n+3)}{(n+1)!\; (n+2)(n+3)(n+4)}= \frac{1}{(n+2)(n+4)}$

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