[tex]3cos^{2} 2x+7sin2x-3=0[/tex]. Created by alienamaslenko. algebra-ru

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August 2022 1 2 Report

[tex]3cos^{2} 2x+7sin2x-3=0[/tex]

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GAHrad 3(1 - sin²2x) + 7sin2x -3=0
3 - 3sin²2x + 7sin2x - 3=0
3 sin²2x - 7sin2x=0
sin2x(3sin2x - 7) = 0

sin2x=0
и 3sin2x -7 = 0

sin 2x = 7/3 >1 -не является
sin 2x =0
2x= π+ πn
x= π/2 + πn/2

5 votes Thanks 4

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